Growth of Bacteria THe number N of bacteria present in

Growth of Bacteria: THe number N of bacteria present in a culture at time t (in hours) obeys the law of uninhibited growth N(t) = 1000e^(0.01*t)

a) Determine the number of bateria at t + 0 hours

b) What is the growth rate of the bateria?

c) What is the population after 4 hours?

d) When will the number of bateria reach 1700?

e) When will the number of bateria double?

Solution

<a> At t+0 hours, the number of bacteria = 1000e^(0.01t)

<b> Growth rate = 0.01 = 1%

<c> After t = 4 hourss,

N = 1000e^(0.04) = 1040.81

<d> Let at t, bacteria be 1700.

Then , 1700 = 1000e^(0.01t)

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