why does fat dissolve in ethanolSolution

why does fat dissolve in ethanol?

Solution

Hydrophobic interactions betwee█ ███████ ██████████████████████████ ████████████ █████ ██████ ██████ ██████ ████ █████████████████

what is 9.807msec2 in miles per hour per second I have

what is 9.807m/sec2 in miles per hour per second? I have been trying this question forever and can\’t get it. please show work so I can understand how to do it please.

Solution

Recall that

\\[1\\,\\text{hour} = 3600\\,\\text{seconds}\\]

\\[1\\,\\text{mile} \\approx 1609\\,\\text{meters}\\]

Write

\\[\\left(9.807\\,\\dfrac{\\text{meter}}{\\text{second} \\cdot \\text{second}}\ ight) \\times \\██████████(\\████████{█████████\\,\\███████{██████████████}}{\\█████████{███████}} \ ███████) \\█████████ \\██████████(\\████████{█\\,\\████████{█████████}}{██████\\,\\██████{████████████}} \ ██████)\\]

████████, ███ ████████ ██████████████████████████ \\(██████████\\,\\███████████{\\██████{█████████}}{\\███████{███████████}\\████████ \\████████{██████████████}}\\)

what is 9.807msec2 in miles per hour per second I have

what is 9.807m/sec2 in miles per hour per second? I have been trying this question forever and can\’t get it. please show work so I can understand how to do it please.

Solution

Recall that

\\[1\\,\\text{hour} = 3600\\,\\text{seconds}\\]

\\[1\\,\\text{mile} \\approx 1609\\,\\text{meters}\\]

Write

\\[\\left(9.807\\,\\dfrac{\\text{meter}}{\\text{second} \\cdot \\text{second}}\ ight) \\times \\███████(\\████████████{████████\\,\\███████{███████████████}}{\\██████████{██████████}} \ ██████) \\████████████ \\██████████(\\███████████{█\\,\\████████{███████}}{█████████\\,\\█████████{█████████████}} \ ██████)\\]

██████, █████ █████████ ███████████████████████████████ \\(████████████\\,\\███████████{\\███████{███████████}}{\\█████████{█████}\\███████████ \\██████{██████████████}}\\)

How do buffers work, by taking advantage of the common

How do buffers work, by taking advantage of the common ion effect? Give an example that could be used to make a buffer with HCN.

Solution

A buffer is a system of a weak acid and its conjugate base or a weak base and its conjugate acid. In the case of HCN, it is a weak acid and it\’s conjugate base would be CN-. You can make a buffer by adding a salt of the conjugate base such as KCN or NaCN to HCN. When an acid is added, it reacts with the CN- ion (the conjugate base) and forms HCN (the weak acid). H+ + ██████ &#█████;> █████ █████████ ██ ███████ █████ ███████████, ████ ██████████████ █████████ ████████ ████████ (█████ █████████ █████████) ███████ ███████ ████████ ██████ ██████ (█████████ █████████████████ █████████)█ ███████ + █████ &#██████████;> ██████ + ████ █████ █████████████ ███████ ███████ ████████████ █████████ ██████████████████ ███ █████ ███████████ █████ ██████████ ████████████████████ ████████ █████ █████ ██████████ ████ █████ █████████ ████ ██████ ███████ █████ ██████ ██████████████████ ███████ ██████, ████████ ██████████████ ███████████████████ █████ ████ ██████████ ██████████████, ██ ██████████████████ ████████ ████ ███ █████████████████████████████ ██████████████████████

factor 2t2-3t+2Solution2t2 – 3t + 2 0 gt t2 – 1.5t +

factor 2t^2-3t+2

Solution

2*t^2 – 3*t + 2 = 0

==> t^2 – 1.5*t + 1 = 0

factors, t = +1.█ (+█████)████████(██████^█ &#███████; █*█*█) ██ ██

= ██████(+████)██*██████████████

= ██████(+████)███*███████

tHE LENGHT OF A NEW RECTAGULAR PLAYING FIRLD IS 9 YARDS

tHE LENGHT OF A NEW RECTAGULAR PLAYING FIRLD IS 9 YARDS LONGER THAN DOUBLE THE WIDTH.IF THE PERIMTER OF THE RECTANGULAR PLAYING FIELD IS 372 YARDS, WHAT ARE ITS DIMENSIONS?

THE WIDTH IS ___ YARDS

THE LENGHT IS ___ YARDS

Solution

length is L

width is W

given length L= 2W+9

perimeter is 2(Length+ width) = 372

2(L+W)=472

█(████+██+███)=██████

██████+████=████

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If aqueous solutions of nitric acid and barium hydroxid

If aqueous solutions of nitric acid and barium hydroxide are mixed, the coefficient of water in the balanced molecular equation is:
and the coefficient of Barium Ion?
what is its driving force!

Solution

2HNO3 + Ba(OH)2 —-> Ba(NO3)2 + 2H20 2H+ 2NO3- + Ba2+ + 2OH█ &#███████;&#██████████;> ██████+ + ███████████ + █████████ █████████████████████ ████ ███████████: ███ ███████████████████████ ████ █████+ = ██

A class of 13 students is trying to decide how they sho

A class of 13 students is trying to decide how they should form themselves into groups of 4 for an upcoming clasroom activity. One of the students first proposes they calculate how many combinations of 4 students can be made from 13 people. After doing the calculations, how many groups of 4 people can be made from a student population of 13 people?

Solution

The formula for this is n!/(x!(n-x)!), where n is the total number of students and x is th█ ████████████ ███ ██████ ██████████ ████ █████████ ███████, █████████ ██████████ ████ ████████████ ████!███(██!(██████████)!) = ██,████████,████████,████████(████*█████,██████) = ███████

After balancing an equation, how do you find the mole r

After balancing an equation, how do you find the mole ratio?

Solution

The mole ratio is the ratio of the coefficients in front of each reactant and product. F███ ████████████████████: ████████ + ██ ███ &#███████████;> █ ████ + █ █████ ███████ ██████ ████████████ ██████████████ █████████████ (████████) █████ ████████ ████ ███████ █████ ███████

1. Determine whether or not the given set forms a basis

1. Determine whether or not the given set forms a basis for the indicated subspace.

{(1,2,-1,3),(0,0,0,0)} for the subspace of R^4 of all vectors of the form (a,b,a-b,a+b)

2. Find a basis for the subspace generated by the given set of vectors.

{(1,-1,0),(0,1,1),(1,0,2)}

3. Extend the given set to form a basis for R^m.

{(-1,1,0,0),(1,-1,1,0),(0,0,1,2)} for R^4.

4. Explain why the given statement is true \”by inspection\”.

The set {(1,-1,2),(0,1,1)} does not span R^3.

Solution

1) The set contains (0,0,0,0) and then as dimension only 1,so cannot be a base of the space given ( dimension 2)

2) {(1,-1,0),(0,1,1),(1,0,2)}

If you have learned about the determinant :

Take the determinant of the matrix

A=

1 0 1

-1 1 0

0 1 2

By expanding by first row :

det(A) = 1*(1*2-1*0) +1*(0*2-1*1) = 1 , which is not 0

So the vectors are linearly independent and for already a base of R^3

If you didn\’t learn about determinant reduce the matrix into row echelon form and you\’ll have the same result ( if any question please ask)

3)

{(-1,1,0,0),(1,-1,1,0),(0,0,1,2),(a,b,c,d)} need to ███ █ █████████ █████ █^██

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